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lelekton Profil * |
#1 · Zasláno: 17. 12. 2014, 16:47:38
zdravim mohl by mi nekdo poradit co delam spatne?
mam tento formular <?php echo" <form action=\"/uprava.php\" method=\"POST\"> <table width=60% > <tr> <td> <label for=\"adresa\">adresa:</label> <input type=\"text\" name=\"adresa\" value=\""; require_once '/tools/db2.php'; $qqq = mysql_query("SELECT * FROM `adresy` WHERE `adresa`='"nejaky email"'"); while ($row = mysql_fetch_object($qqq)) {echo "$row->email";} echo"\"> </td> </tr> </table> <div><label for=\"text\">jmeno:</label></div> <input type=\"text\" name=\"jmeno\" value = \"" require_once '/toolsz/db2.php'; $qqq = mysql_query("SELECT * FROM `help` WHERE `address`='".$notf."'"); while ($row = mysql_fetch_object($qqq)) {echo "$row->content";} echo"\"> <div><input type=\"submit\" value=\"submit\" name=\"submit\"></div> </form> "; ?> uprava.php: <?php if(isset($_POST['delete'])){ $tb="adresy"; $jmeno = $_POST['jmeno']; $adresa = $_POST['adresa']; ?> <?php include '/tools/db2.php'; ?> <?php mysql_select_db($DB, $link0); $update=mysql_query("UPDATE `$tb` SET `adresa` = '$adresa' AND `jmeno` = '$jmeno' WHERE `adresa` = '$adresa'", $link0); } ?> nevyhazuje to zadny error ale nic se neupravi nevite v cem delam chybu? |
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Taps Profil |
#2 · Zasláno: 17. 12. 2014, 16:59:10
lelekton:
a jaký error to ukáže,když použiješ níže uvedené? $update=mysql_query("UPDATE `$tb` SET `adresa` = '$adresa' AND `jmeno` = '$jmeno' WHERE `adresa` = '$adresa'", $link0) or die (mysql_error()); |
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tiso Profil |
#3 · Zasláno: 17. 12. 2014, 19:12:39
$update=mysql_query("UPDATE `$tb` SET `adresa` = '$adresa' AND `jmeno` = '$jmeno' WHERE `adresa` = '$adresa'", $link0); |
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Časová prodleva: 9 let
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