volání php pomocí ajaxu

 <form name="multiform" action="./add-video.php" id="multiform" method="post" enctype="multipart/form-data" ><br />
          <input type="text" name="nadpisvidea" size="39" /><br />
          <input type="file" name="photo" id="video" accept="video/mp4, video/avi" /><br />     
          <input type="file" name="fotovidea" id="fotovidea" accept="image/x-png, image/gif, image/jpeg" /><br />
<textarea name="popis" style="width:800px;height:200px;" /></textarea>                    
        <td align="right">
          <input type="submit" name="okey" value="pridat" />
      </form>                                                                                                                                
    </center>       
    <div id="videa" style="width:100%;height:200px;">
    </div> 

<?php
  include "./header.php"; 
  include "./config.php"; ?>        
 <?php


   
    if(isset($_POST["okey"])){
      $nadpisvidea = $_POST["nadpisvidea"];
      $fotovidea = $_POST["fotovidea"];
      $video = $_POST["video"];
      $popis = $_POST["popis"];
      $smazane = "0";
                             
      $zapis = mysql_query("INSERT INTO videa SET nadpisvidea='$nadpisvidea',smazane='$smazane', popis='$popis', video='video/$nadpisvidea.mp4', fotovidea='video/$nadpisvidea.jpg' ;"); 
      move_uploaded_file($_FILES["video"]["tmp_name"],"./video/$nadpisvidea.mp4");
      move_uploaded_file($_FILES["fotovidea"]["tmp_name"],"./video/$nadpisvidea.jpg");
      
      echo "Video bylo úspěšně uloženo";

    } else {  echo "chyba.";  }                                    
                                               
  ?>