screenshot stránky podla url (väčšia kvalita obrázku)

                    
<img id="testImage" data-url="' . $url . '">';
    <script src="//ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
    <script>
    $(window).load(function() {
    $('img[data-url]').each(function() {
        $.ajax({
            url: 'https://www.googleapis.com/pagespeedonline/v1/runPagespeed?url=' + $(this).data('url') + '&screenshot=true',
            context: this,
            type: 'GET',
            dataType: 'json',
            success: function(data) {
                   data = data.screenshot.data.replace(/_/g, '/').replace(/-/g, '+');
                $(this).attr('src', 'data:image/png;base64,' + data);
                $(this).attr('data-pagespeed-high-res-src', 'data:image/png;base64,' + data);
            }
        });
    });
});