Autor Zpráva
stepi15
Profil
zdravim sikovne programatory
Nasel by se tu nekdo kdo by me udelal script na odpocet datumu do 6.1.2009?

predem diky
king26
Profil
HTML:
                           <div id="countdowncontainer2"></div>
                            <script type="text/javascript">
                             var currentyear=new Date().getFullYear()
                             var christmas=new cdtime("countdowncontainer2", "June 22, 2008 16:00:00")
                             christmas.displaycountdown("days", formatresults2)
                            </script>


JS:
function cdtime(container, targetdate){
if (!document.getElementById || !document.getElementById(container)) return
this.container=document.getElementById(container)
this.currentTime=new Date()
this.targetdate=new Date(targetdate)
this.timesup=false
this.updateTime()
}

cdtime.prototype.updateTime=function(){
var thisobj=this
this.currentTime.setSeconds(this.currentTime.getSeconds()+1)
setTimeout(function(){thisobj.updateTime()}, 1000) //update time every second
}

cdtime.prototype.displaycountdown=function(baseunit, functionref){
this.baseunit=baseunit
this.formatresults=functionref
this.showresults()
}

cdtime.prototype.showresults=function(){
var thisobj=this


var timediff=(this.targetdate-this.currentTime)/1000 //difference btw target date and current date, in seconds
if (timediff<0){ //if time is up
this.timesup=true
this.container.innerHTML=this.formatresults()
return
}
var oneMinute=60 //minute unit in seconds
var oneHour=60*60 //hour unit in seconds
var oneDay=60*60*24 //day unit in seconds
var dayfield=Math.floor(timediff/oneDay)
var hourfield=Math.floor((timediff-dayfield*oneDay)/oneHour)
var minutefield=Math.floor((timediff-dayfield*oneDay-hourfield*oneHour)/on eMinute)
var secondfield=Math.floor((timediff-dayfield*oneDay-hourfield*oneHour-min utefield*oneMinute))
if (this.baseunit=="hours"){ //if base unit is hours, set "hourfield" to be topmost level
hourfield=dayfield*24+hourfield
dayfield="n/a"
}
else if (this.baseunit=="minutes"){ //if base unit is minutes, set "minutefield" to be topmost level
minutefield=dayfield*24*60+hourfield*60+minutefield
dayfield=hourfield="n/a"
}
else if (this.baseunit=="secunds"){ //if base unit is seconds, set "secondfield" to be topmost level
var secondfield=timediff
dayfield=hourfield=minutefield="n/a"
}
this.container.innerHTML=this.formatresults(dayfield, hourfield, minutefield, secondfield)
setTimeout(function(){thisobj.showresults()}, 1000) //update results every second
}

/////CUSTOM FORMAT OUTPUT FUNCTIONS BELOW//////////////////////////////

//Create your own custom format function to pass into cdtime.displaycountdown()
//Use arguments[0] to access "Days" left
//Use arguments[1] to access "Hours" left
//Use arguments[2] to access "Minutes" left
//Use arguments[3] to access "Secunds" left

//The values of these arguments may change depending on the "baseunit" parameter of cdtime.displaycountdown()
//For example, if "baseunit" is set to "hours", arguments[0] becomes meaningless and contains "n/a"
//For example, if "baseunit" is set to "minutes", arguments[0] and arguments[1] become meaningless etc

function formatresults2(){
if (this.timesup==false){ //if target date/time not yet met
var displaystring="<span class='odpocitavani'>"+arguments[0]+" <sup>Days</sup> "+arguments[1]+" <sup>Hours</sup> "+arguments[2]+" <sup>Minutes</sup> "+arguments[3]+" <sup>Secunds</sup></span>"
}
else{ //else if target date/time met
var displaystring="<span class='odpocitavani'>Live! Czech vs. Italy!</span>" //Don't display any text
}
return displaystring
}


CSS:
.odpocitavani {border: 2px dotted grey;color:green;font: bold 18px MS Sans Serif;padding: 3px;}
.odpocitavani sup {font-size: 80%;}
stepi15
Profil
ja bych to potreboval v php proto to je v kategorii PHP
Nadan
Profil
Hhe, to potěší... Ten se tu s tím smolí... :D
jansfabik
Profil
stepi15: nepíše se DATUMU ale data ;-)

jde to udělat například takto:
$cas = mktime(0,0,0,1,6,2009);
$cas2 = time();
$rozdil = $cas-$cas2;  // v proměnné rozdil je počet sekund do toho data
echo 'Do 6.1.2009 zbývá ';
echo floor($rozdil/(24*3600)).' dní, ';
$rozdil = $rozdil%(24*3600);
echo floor($rozdil/3600).' hodin, ';
$rozdil = $rozdil%3600;
echo floor($rozdil/60).' minut a ';
$rozdil = $rozdil%60;
echo $rozdil.' sekund.';
stepi15
Profil
diky bude ten script presny kdyz treba listopad ma 30 dnu a prosinec 31?
jansfabik
Profil
ano, bude

Vaše odpověď

Mohlo by se hodit

Odkud se sem odkazuje


Prosím používejte diakritiku a interpunkci.

Ochrana proti spamu. Napište prosím číslo dvě-sta čtyřicet-sedm: